9x^2-48x-48=0

Solution for 9x^2-48x-48=0 equation:

9x^2-48x-48=0

a = 9; b = -48; c = -48;
Δ = b2-4ac
Δ = -482-4·9·(-48)
Δ = 4032
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4032}=\sqrt{576*7}=\sqrt{576}*\sqrt{7}=24\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-24\sqrt{7}}{2*9}=\frac{48-24\sqrt{7}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+24\sqrt{7}}{2*9}=\frac{48+24\sqrt{7}}{18}
$